(3y^2+1)-(4+2y^2)=

Solution for (3y^2+1)-(4+2y^2)= equation:

Simplifying
(3y2 + 1) + -1(4 + 2y2) = 0

Reorder the terms:
(1 + 3y2) + -1(4 + 2y2) = 0

Remove parenthesis around (1 + 3y2)
1 + 3y2 + -1(4 + 2y2) = 0
1 + 3y2 + (4 * -1 + 2y2 * -1) = 0
1 + 3y2 + (-4 + -2y2) = 0

Reorder the terms:
1 + -4 + 3y2 + -2y2 = 0

Combine like terms: 1 + -4 = -3
-3 + 3y2 + -2y2 = 0

Combine like terms: 3y2 + -2y2 = 1y2
-3 + 1y2 = 0

Solving
-3 + 1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 1y2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 1y2 = 0 + 3
1y2 = 0 + 3

Combine like terms: 0 + 3 = 3
1y2 = 3

Divide each side by '1'.
y2 = 3

Simplifying
y2 = 3

Take the square root of each side:
y = {-1.732050808, 1.732050808}